Author Topic: Math Help  (Read 4772 times)

Offline freeziez

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Math Help
« on: May 03, 2011, 06:42:29 PM »
I can't see the chatterbox, so I posted it here. :P



How do you solve this?
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Offline Preytor_4

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Re: Math Help
« Reply #1 on: May 03, 2011, 06:46:12 PM »
Cause this is going to work so well.

Offline freeziez

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Re: Math Help
« Reply #2 on: May 03, 2011, 06:50:28 PM »
Cause this is going to work so well.

I just need help... :confused:

I'm doing my Algebra I homework now, so I need an answer or even a step quick.
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Offline HurricaneAndrew

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Re: Math Help
« Reply #3 on: May 03, 2011, 06:51:22 PM »
Hell if I know... I shouldn't have passed math in high school, but it was my senior year and they didn't want to deal with me for another whole year.  :laughing
 
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Offline NFX

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Re: Math Help
« Reply #4 on: May 03, 2011, 06:59:51 PM »
Start by multiplying both parts by (2c+2)(c-1) to get rid of the bottom halves of the equation. What does it equal, by the way?
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Offline NFX

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Re: Math Help
« Reply #5 on: May 03, 2011, 07:04:09 PM »
Are you trying to figure out what c is? Because you need some sort of equivelant for the equation you have at the moment, otherwise it makes absolutely no sense. 6c is meaningless on its own, but 6c=30 is easy enough to solve. You see what I mean there? =]
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Offline Fracture

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Re: Math Help
« Reply #6 on: May 03, 2011, 07:04:10 PM »
[4c/(2c + 2)] x [(c^2 + 3c + 2)/(c-1)]
= (2 + 2c) x (c - c^2) + (3 - 3c) + (2/c - 2)
= 2 + 2c x c - c^2 + 3 - 3c + 2/c - 2
= 2 + 2c^2 - c^2 + 3 - 3c + 2/c - 2
= 3 + c^2 - 3c + 2/c

LOL that's totally wrong but I tried. I just came here to tell you to check your PMs. :P

What does it equal, by the way?

I'm pretty sure he's trying to simplify it rather than solve it.

Offline freeziez

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Re: Math Help
« Reply #7 on: May 03, 2011, 07:05:00 PM »
Okay, I'm getting this.

But first, what's (c+2) / (c-1)?

What does it equal, by the way?

I'm pretty sure he's trying to simplify it rather than solve it.

Yeah, I have to simplify it down to the smallest expression possible, where I cannot possibly find c.
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Offline NFX

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Re: Math Help
« Reply #8 on: May 03, 2011, 07:10:33 PM »
Ah, I see. Been at least two years since I did this sort of thing. So multiplying it out would be the first step.

(4c/[2c+2])x([c^2+3c+2]/[c-1])
=(4c[c-1])x([c^2+3c+2][2c+2])
=(4c^2 - 4c) x (2c^3 + 8c^2 + 10c + 4)
=(8c^5 + 24c^4 + 8c^3 - 24c^2 - 16c)

I think that should be the answer. No denominators and such. =]
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Offline Fracture

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Re: Math Help
« Reply #9 on: May 03, 2011, 07:11:38 PM »
Okay, I'm getting this.

But first, what's (c+2) / (c-1)?

1 + 1/2c - c - 2? (I'm just guessing btw, if I turn out to be right I'll throw a party)

Offline 090901

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Re: Math Help
« Reply #10 on: May 03, 2011, 07:12:52 PM »
I can't see the chatterbox, so I posted it here. :P

(Image removed from quote.)

How do you solve this?
First part:
2c/c +2
Second part
c+3+2/ -1




This took me less then 5 mins :P

Offline NFX

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Re: Math Help
« Reply #11 on: May 03, 2011, 07:15:30 PM »
I can't see the chatterbox, so I posted it here. :P

(Image removed from quote.)

How do you solve this?
First part:
2c/c +2
Second part
c+3+2/ -1

I'm afraid I have to mention you're wrong on that one. =] First part, you have to divide everything on the bottom by two if you're doing it that way, and the second part, c is not a factor of 2, and you've just left it there. I'm pretty sure I've gotten it right, provided I've not overlooked anything stupid.
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Offline 090901

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Re: Math Help
« Reply #12 on: May 03, 2011, 07:18:08 PM »
I can't see the chatterbox, so I posted it here. :P

(Image removed from quote.)

How do you solve this?
First part:
2c/c +2
Second part
c+3+2/ -1

I'm afraid I have to mention you're wrong on that one. =] First part, you have to divide everything on the bottom by two if you're doing it that way, and the second part, c is not a factor of 2, and you've just left it there. I'm pretty sure I've gotten it right, provided I've not overlooked anything stupid.
tbh, i was just doing what i remembered from earlier this year when we learned this, so it pretty much proves it doesn't stick even though i'm a honors student :P

Offline Enigm@

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Re: Math Help
« Reply #13 on: May 03, 2011, 07:23:59 PM »
[lmgtfy]Calculator[/lmgtfy]
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Offline freeziez

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Re: Math Help
« Reply #14 on: May 03, 2011, 07:26:40 PM »


That's how you do it. :3
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Offline Enigm@

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Re: Math Help
« Reply #15 on: May 03, 2011, 07:29:42 PM »
(Image removed from quote.)

That's how you do it. :3
What the heck was the point of making this thread then?
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Offline Hydro

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Re: Math Help
« Reply #16 on: May 03, 2011, 07:31:44 PM »
EXPONENNNNTTTTSSSS

Hi.

Offline 090901

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Re: Math Help
« Reply #17 on: May 03, 2011, 07:34:57 PM »
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That's how you do it. :3
What the heck was the point of making this thread then?
QFT
now i must stop slacking off and finish my math homework :P

Offline freeziez

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Re: Math Help
« Reply #18 on: May 03, 2011, 07:36:31 PM »
(Image removed from quote.)

That's how you do it. :3
What the heck was the point of making this thread then?
QFT

Well, NFX and Fracture helped me get the first 3 steps down, which I didn't have before, and I just did the rest myself. Then I typed it up on Paint.

So it's not like it was for teh lulz.
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Offline Hydro

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Re: Math Help
« Reply #19 on: May 03, 2011, 07:39:06 PM »
*begins throwing segments of trigonometry around the room before bashing his head through the wall repeatedly*
Hi.