The Beauty of Math

[ACAMS]

2+2=4 (I think)

[Madiaba]

Didn't know you knew quadratics, ACAMS.  Impressive.
*studies equation*

[kill343gs]

You can not perform an equation with infinity because you can not reach infinity, only approach it.

[Naryar]

No you can. In math there is a way of approximating an equation when x goes to infinity.

Example:

1/Infinity = 0 (see y=1/x)

-1/Infinity = 0 (same)

Infinity*Infinity = Infinity

Infinity^k = infinity (k being a positive number)

Infinity^-k = 0 (k still positive)

Infinity*-k = -Infinity

Infinity*0 = 0

Etc.

And with this technique you can approximately divide by zero (Apocalypse!)

k/0 = Infinity
-k/0 = -Infinity

But 0/0 doesn't exist.

[Sage]

infinity*0 would be 0 i thought. anything times 0 is 0.

[Naryar]

You're right. Edited.

[man manu]

@man manu: 2. not even math really.

heres a question:

theres an undefined line and a line with the slope zero. they are perpendicular to each other. whats the slope of the undefined line?

'twas an answer to gigas question.

[man manu]

times and simplyfy these dudes

(x+4)(x+8)
(x+y)(x-3)

[Serge]

times and simplyfy these dudes

(x+4)(x+8)
(x+y)(x-3)

= x^2 + 8x + 4x + 32 = x^2 + 12x + 32 = x^2 + 4(3x + 8) ?

= x^2 - 3x + yx -3y = x(y + x) - 3(y + x) ?

[Somebody]

There is no infinity, counting just goes forever. Same as pi (at least to 1 million decimals.)

[Clickbeetle]

0 + 0 + 0 + 0 + 0 +... = 0

(1-1) + (1-1) + (1-1) + (1-1) + (1-1) +... = 0

1 + -1 + 1 + -1 + 1 + -1 + 1 + -1 + 1 + -1 +... = 0

1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1) +... = 0

1 + 0 + 0 + 0 + 0 +... = 0

1 = 0

[Sage]

1+0=1, not 0.

[Clickbeetle]

The point is that all of the quantities on the left are equal to each other (sort of).  It's just rearranging parentheses.  "..." means it's an infinite series.

I know 0 doesn't equal 1, but that's a fun way to make it look like it does.

Here's another one you might have seen if you typed cheatbot2 in DSL.

3 guys go to a restaurant and each order a $10 meal. They pay the waiter $30 who goes to the register and finds out there's a special, $5 off your purchase. He goes back and gives each guy $1 and pockets the other $2 since he doesn't know how to divide it. So each guy ends up paying $9 for a total of $27, plus the $2 with the waiter makes $29. Where is the other dollar?

[ACAMS]

1 + 0 + 0 + 0 + 0 +... = 0

 
I have to disagree with that eqation.

[Sage]

The point is that all of the quantities on the left are equal to each other (sort of).  It's just rearranging parentheses.  "..." means it's an infinite series.

I know 0 doesn't equal 1, but that's a fun way to make it look like it does.

Here's another one you might have seen if you typed cheatbot2 in DSL.

3 guys go to a restaurant and each order a $10 meal. They pay the waiter $30 who goes to the register and finds out there's a special, $5 off your purchase. He goes back and gives each guy $1 and pockets the other $2 since he doesn't know how to divide it. So each guy ends up paying $9 for a total of $27, plus the $2 with the waiter makes $29. Where is the other dollar?

you can't subtract the 3 dollars then add the 2 dollars. when each guy pays $9 dollars, you are subtracting $3, making $27. you can't then add the waiter's $2. you have to subtract it, making it $25 dollars, the amount of the discount.

[man manu]

the waitor gives one of the guys $1

[Serge]

I have to disagree with that eqation.

True, since:

Code: [Select]

1 + -1 + 1 + -1 + 1 + -1 = 0
1 + (-1 + 1 + -1 + 1) -1 = 0 (there is a trailing -1 at the end!)
1 + (       0       ) -1 = 0
1 +                   -1 = 0


1 + -1 = 0

[Madiaba]

Though I've not taught math, I've taught physics. I ran across this pic of a 'quiz problem' online that just made me laugh...
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[somestrangeguy]

[Somebody]

Whoa. I just tried that and it works. Google, you have lied, and now you will die.

Execution Date: When the world blows up:evil: