gametechmods
Off-Topic => Chatterbox => Topic started by: ACAMS on September 19, 2007, 11:57:52 PM
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Beauty of Math !
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1 x 8 + 1 = 9
12 x 8 + 2 = 98
123 x 8 + 3 = 987
1234 x 8 + 4 = 9876
12345 x 8 + 5 = 98765
123456 x 8 + 6 = 987654
1234567 x 8 + 7 = 9876543
12345678 x 8 + 8 = 98765432
123456789 x 8 + 9 = 987654321
1 x 9 + 2 = 11
12 x 9 + 3 = 111
123 x 9 + 4 = 1111
1234 x 9 + 5 = 11111
12345 x 9 + 6 = 111111
123456 x 9 + 7 = 1111111
1234567 x 9 + 8 = 11111111
12345678 x 9 + 9 = 111111111
123456789 x 9 +10= 1111111111
9 x 9 + 7 = 88
98 x 9 + 6 = 888
987 x 9 + 5 = 8888
9876 x 9 + 4 = 88888
98765 x 9 + 3 = 888888
987654 x 9 + 2 = 8888888
9876543 x 9 + 1 = 88888888
98765432 x 9 + 0 = 888888888
And look at this symmetry:
1 x 1 = 1
11 x 11 = 121
111 x 111 = 12321
1111 x 1111 = 1234321
11111 x 11111 = 123454321
111111 x 111111 = 12345654321
1111111 x 1111111 = 1234567654321
11111111 x 11111111 = 123456787654321
111111111 x 111111111=123456789 87654321
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Wow! Wow! Wow!
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Remember the song, "12 Days of Christmas"? How many presentss were received during those twelve days?
Look:
On the:
1st day - 1 present (a partridge in a pear tree - I'm not going through all of 'em)
2nd day - 2 + 1 = 3
3rd day - 3 + 2 +1 = 6
4th day - 4 + 3 + 2 + 1 = 10
5th day - 5 + 4 + 3 + 2 + 1 = 15
6th day - 6 + 5 + 4 + 3 + 2 + 1 = 21
7th day - 7 + 6 + 5 + 4 + 3 + 2 + 1 = 28
8th day - 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 36
9th day - 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45
10th day - 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 55
11th day - 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 66
12th day - 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 78
Sooo.. 1+3+6+10+15+21+28+36+45+55+66+78 = 364 +1 (Christmas Day) = 365, or the number of days in a year .....
Somewhere, a friend and I also figured out how much all of these things would cost, too - as soon as i find it. I'll post it.
For some other good and interesting math equations, try the "Necroscope" series by Brian Lumley - some very intriguing mathematical questions woven into the story.....
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booooo....
i hate math lol O_o
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(https://gametechmods.com/uploads/images/19399Math Fail.png)
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(http://www.photocactus.com/thumbs/5165find_x.gif)
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Lol, that's a good one. =P
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x=5
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Sage you're awesome.
Anyways,
(http://www.chezpilou.info/public/Inclassables/math_fail_2.jpg)
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hey naryar, looks like you're getting some reputation. congrats.
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hey naryar, looks like you're getting some reputation. congrats.
Good or bad? :icon_twisted:
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Good or bad? :icon_twisted:
you never can tell can you.
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Ive seen the one goose did many times, and I still think its funny
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3y + 6x=18
Find the y and x intercepts, and slope.
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(https://gametechmods.com/uploads/images/86250Untitled.png)
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slope= -2, y-intercept= 6, x-intercept= 3
(answer to somebody's question)
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Correct! :-D
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(http://img231.imageshack.us/img231/11/equationpm6.png)
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How did you get " a - 1 = a + 1 " ?
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Another one:
(http://img231.imageshack.us/img231/2074/girlevilll8.png)
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How did you get " a - 1 = a + 1 " ?
I divided both sides by (a - 1).
No, sh** dammit, I made a mistake. I'll fix the image in a sec.
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Here, fixed.
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That's better.
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I don't see how the hell do you jump from a-1=(a-1)*(a+1) to a-1=a+1...
And you forgot something important: the equation a^2 =1 admits TWO values of a: a=1and a =-1. So, a=1 => a^2=1 goes one way (the opposite isn't true) but all of the others goes both way (mathematical symbol <=>).
With a=-1 the thing works.
I bet that can be solved by imaginary numbers but I'm too lazy to use them now.
Yeah, I'm a math nerd.
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I don't see how the hell do you jump from a-1=(a-1)*(a+1) to a-1=a+1...
And you forgot something important: the equation a^2 =1 admits TWO values of a: a=1and a =-1. So, a=1 => a^2=1 goes one way (the opposite isn't true) but all of the others goes both way (mathematical symbol <=>).
With a=-1 the thing works.
I bet that can be solved by imaginary numbers but I'm too lazy to use them now.
Yeah, I'm a math nerd.
The first error was fixed, my bad, I am tired, refresh the image.
As for the confusion with a^2... I am nowhere telling that sqrt(a^2) = 1, so I do not need absolute values or deal with multiple cases.
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An easy question:
Solve this problem without using the number 2 or anything that 2, 2.5, 1.5, or 7 is divisible by. Yet the numbers that create the product must be a whole number, equal to 2 and greater than 1.
1+1 = ?
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square root of 4.
you said '2 is divisible by' instead of 'divisble by 2'
otherwise just 5-3
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Nu uh (smiley face)... Fixed =)
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Haha, thats a good one Serge ;)
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-1+3?
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@man manu: 2. not even math really.
heres a question:
theres an undefined line and a line with the slope zero. they are perpendicular to each other. whats the slope of the undefined line?
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@man manu: 2. not even math really.
heres a question:
theres an undefined line and a line with the slope zero. they are perpendicular to each other. whats the slope of the undefined line?
The undefined line cannot be the graph of a function, since in a function no argument can result in more than one value (where in this case, there is an infinite numbers of values).
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incorrect
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No, he's right.
This can't have any slope because if we consider it in a classic two-dimensional space (cartesian coordinates) with Ox and Oy as vectors, that (vertical) line would have an equation of x=k (k being a constant and y being free).
Problem, you can't have a slope (or can't get a derivative for being more precise) from such a function.
Common sense would say the value of the slope is fixed and infinite, but this is a math abomination.
So you can't have any slope on there, excepted if you're tricking us with 3D space.
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well, from what i know, an undefined slope= a vertical line. if a slope = 0 then its horizontal, meaning they form a perpendicular. the answer was in the question.
the slope is undefined, because in the slope formula the answer would be something divided by zero, which is impossible, making it a vertical line.
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Basically, since slope is rise of the line over the run, having a completely vertical line is mathematically impossible from my understanding. The slope would be infinity divided by zero. In a distance over time graph (one measuring speed), such a line would mean that the object is everywhere in the universe at the same time.
(http://img231.imageshack.us/img231/11/equationpm6.png)
There is a flaw in the fourth line here. a-1 = (a-1)(a+1) should equal a-1 = a^2-1
which is 0=0, not 1=2 :P
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What is the square root of infinity?
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What is the square root of infinity?
pi.
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Infinity too!
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Basically, since slope is rise of the line over the run, having a completely vertical line is mathematically impossible from my understanding. The slope would be infinity divided by zero. In a distance over time graph (one measuring speed), such a line would mean that the object is everywhere in the universe at the same time.
There is a flaw in the fourth line here. a-1 = (a-1)(a+1) should equal a-1 = a^2-1
which is 0=0, not 1=2 :P
There is nothing wrong with this line. The error is somewhere else.
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2+2=4 (I think)
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Didn't know you knew quadratics, ACAMS. Impressive.
*studies equation*
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You can not perform an equation with infinity because you can not reach infinity, only approach it.
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No you can. In math there is a way of approximating an equation when x goes to infinity.
Example:
1/Infinity = 0 (see y=1/x)
-1/Infinity = 0 (same)
Infinity*Infinity = Infinity
Infinity^k = infinity (k being a positive number)
Infinity^-k = 0 (k still positive)
Infinity*-k = -Infinity
Infinity*0 = 0
Etc.
And with this technique you can approximately divide by zero (Apocalypse!)
k/0 = Infinity
-k/0 = -Infinity
But 0/0 doesn't exist.
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infinity*0 would be 0 i thought. anything times 0 is 0.
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You're right. Edited.
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@man manu: 2. not even math really.
heres a question:
theres an undefined line and a line with the slope zero. they are perpendicular to each other. whats the slope of the undefined line?
'twas an answer to gigas question.
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times and simplyfy these dudes
(x+4)(x+8)
(x+y)(x-3)
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times and simplyfy these dudes
(x+4)(x+8)
(x+y)(x-3)
= x^2 + 8x + 4x + 32 = x^2 + 12x + 32 = x^2 + 4(3x + 8) ?
= x^2 - 3x + yx -3y = x(y + x) - 3(y + x) ?
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There is no infinity, counting just goes forever. Same as pi (at least to 1 million decimals.)
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0 + 0 + 0 + 0 + 0 +... = 0
(1-1) + (1-1) + (1-1) + (1-1) + (1-1) +... = 0
1 + -1 + 1 + -1 + 1 + -1 + 1 + -1 + 1 + -1 +... = 0
1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + (-1 + 1) +... = 0
1 + 0 + 0 + 0 + 0 +... = 0
1 = 0
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1+0=1, not 0.
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The point is that all of the quantities on the left are equal to each other (sort of). It's just rearranging parentheses. "..." means it's an infinite series.
I know 0 doesn't equal 1, but that's a fun way to make it look like it does.
Here's another one you might have seen if you typed cheatbot2 in DSL.
3 guys go to a restaurant and each order a $10 meal. They pay the waiter $30 who goes to the register and finds out there's a special, $5 off your purchase. He goes back and gives each guy $1 and pockets the other $2 since he doesn't know how to divide it. So each guy ends up paying $9 for a total of $27, plus the $2 with the waiter makes $29. Where is the other dollar?
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1 + 0 + 0 + 0 + 0 +... = 0
I have to disagree with that eqation.
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The point is that all of the quantities on the left are equal to each other (sort of). It's just rearranging parentheses. "..." means it's an infinite series.
I know 0 doesn't equal 1, but that's a fun way to make it look like it does.
Here's another one you might have seen if you typed cheatbot2 in DSL.
3 guys go to a restaurant and each order a $10 meal. They pay the waiter $30 who goes to the register and finds out there's a special, $5 off your purchase. He goes back and gives each guy $1 and pockets the other $2 since he doesn't know how to divide it. So each guy ends up paying $9 for a total of $27, plus the $2 with the waiter makes $29. Where is the other dollar?
you can't subtract the 3 dollars then add the 2 dollars. when each guy pays $9 dollars, you are subtracting $3, making $27. you can't then add the waiter's $2. you have to subtract it, making it $25 dollars, the amount of the discount.
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the waitor gives one of the guys $1
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I have to disagree with that eqation.
True, since:
1 + -1 + 1 + -1 + 1 + -1 = 0
1 + (-1 + 1 + -1 + 1) -1 = 0 (there is a trailing -1 at the end!)
1 + ( 0 ) -1 = 0
1 + -1 = 0
1 + -1 = 0
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Though I've not taught math, I've taught physics. I ran across this pic of a 'quiz problem' online that just made me laugh...
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(https://gametechmods.com/uploads/images/40318Physics%20Problem.jpg)
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(http://kuvaton.com/bsh**/google-calculator.png)
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Whoa. I just tried that and it works. Google, you have lied, and now you will die.
Execution Date: When the world blows up:evil:
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If someone says a penny for your thoughts, and you give him your two cents worth, what happened to the other penny?
A duck, a frog, and a skunk walk into a bar.
Each orders a drink.
The duck pays, because he's got a bill.
The frog pays, because he's got a greenback.
The skunk can't pay, because he's only got a scent.......